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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. int main() {
  5. 	int cases, num, count;
  6. 	cin>>cases;
  7.  
  8. 	for(int i=0; i<cases; i++){
  9. 		cin>>num;
  10. 		count = 0;
  11. 		for(int k=1; k<num; k++){
  12. 			if(num%k == 0){
  13. 				count+=k; 
  14. 			}
  15. 		}
  16. 		if(count>num){
  17. 			cout<<num<<" is an abundant number."<<endl;
  18. 		}
  19. 		else if(count<num){
  20. 			cout<<num<<" is a deficient number."<<endl;
  21. 		}
  22. 		else{
  23. 			cout<<num<<" is a perfect number."<<endl;
  24. 		}
  25. 	}
  26. 	return 0;
  27. }
Success #stdin #stdout 0s 3416KB
comments (?)
stdin
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3
4
6
12
stdout
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4 is a deficient number.
6 is a perfect number.
12 is an abundant number.
https://ideone.com/YLHQCU
language:
C++14 (gcc 8.3)
created:
8 years ago
visibility:
public

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