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  1. f = @(n)ceil(n/3)*(mod(-n,3)-1)
  2.  
  3. f(1)
  4. f(12)
  5. f(77)
  6. f(135)
  7. f(297)
Success #stdin #stdout 0.45s 121792KB
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Standard input is empty
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f =

@(n) ceil (n / 3) * (mod (-n, 3) - 1)

ans =  1
ans = -4
ans = 0
ans = -45
ans = -99
https://ideone.com/WsepZL
language:
Octave (octave 4.4.1)
created:
7 years ago
visibility:
public

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