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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. int main() {
  5.     // your code goes here
  6.     long a,b;
  7.     a = 2147483647;
  8.     b = 1000;
  9.     printf("%.2f",(double)a/(double)b);  // No need to cast both a/(double)b is enough
  10.     return 0;
  11. }
Success #stdin #stdout 0s 16064KB
comments (?)
stdin 
Standard input is empty
stdout 
2147483.65
https://ideone.com/VITPdo
language:
C++ (gcc 8.3)
created:
8 years ago
visibility:
public

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