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  1. #include <stdio.h>
  2. int main (void)
  3. {
  4.     int x, y = 1, z[19];
  5.     unsigned long long int p;
  6.     for (x = 0, y; x <= 20; ++x, ++y)
  7.     {
  8.         z[x] = y;
  9.     }
  10.  
  11.     for (p = 100000; p <= 9999999999999; ++p)
  12.     {
  13.  
  14.          if (p % z[1] == 0 && p % z[2] == 0 && p % z[3] == 0 && p % z[4] == 0 && p % z[5] == 0 && p % z[6] == 0 && p % z[7] == 0 && p % z[8] == 0 && p % z[9] == 0 && p % z[10] == 0 && p % z[11] == 0 && p % z[12] == 0 && p % z[13] == 0 && p % z[14] == 0 && p % z[15] == 0 && p % z[16] == 0 && p % z[17] == 0 && p % z[18] == 0 && p % z[19] == 0)
  15.          printf ("%llu\n", p);
  16.          break;
  17.  
  18.     }
  19.  
  20.     return 0;
  21.  
  22. }
Success #stdin #stdout 0s 2288KB
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https://ideone.com/V2vYQZ
language:
C (gcc 8.3)
created:
10 years ago
visibility:
public

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