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  1. def compare_consecutive_cols(lst):
  2.     res = [0 for i in xrange(len(lst[0]) / 2)]
  3.     for i in xrange(len(lst)):
  4.         for j in xrange(0, len(lst[i]), 2):
  5.             if lst[i][j] == lst[i][j+1]:
  6.                 res[j / 2] += 1
  7.     return res
  8.  
  9. A = [[1, 1, 1, 0, 1, 0], [0, 0, 0, 0, 0, 1]]
  10. print compare_consecutive_cols(A)
  11.  
Success #stdin #stdout 0s 9024KB
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Standard input is empty
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[2, 1, 0]
https://ideone.com/ToHkUC
language:
Python (cpython 2.7.16)
created:
7 years ago
visibility:
public

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