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  1. // ２　a = 3.1, b = 2.9, c = －1.1, d = 5.3の最大値、最小値を求め画面に出力する
  2. #include <stdio.h>
  3.  
  4. #define max(a,b) (a>b?a:b)
  5. #define min(a,b) (a<b?a:b)
  6.  
  7. int main()
  8. {
  9. 	double a = 3.1, b = 2.9, c = -1.1, d = 5.3;
  10.  
  11. 	printf("最大値:%f\n", max(a,max(b,max(c,d))));
  12. 	printf("最小値:%f\n", min(a,min(b,min(c,d))));
  13. 	return 0;
  14. }
  15.  
Success #stdin #stdout 0.02s 1676KB
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Standard input is empty
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最大値:5.300000
最小値:-1.100000
https://ideone.com/SVZIv
language:
C (gcc 8.3)
created:
12 years ago
visibility:
public

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