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  1. E = [4 4 9];
  2. n = sum( E );
  3. I = zeros( 1, n );
  4. I(cumsum( [ 1 E(1:end-1) ] ) ) = 1
  5. I = cumsum( I )
Success #stdin #stdout 0.17s 65056KB
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I =

   1   0   0   0   1   0   0   0   1   0   0   0   0   0   0   0   0

I =

   1   1   1   1   2   2   2   2   3   3   3   3   3   3   3   3   3
https://ideone.com/SFUC1e
language:
Octave (octave 4.4.1)
created:
11 years ago
visibility:
public

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