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  1. a=[1,5,6,8,10]
  2. b=len(a)*[None]
  3. k=int(raw_input()) #rotation factor
  4. b[:]=a[(k-1):]
  5. #print b
  6. b[len(b):]=a[0:len(a)-len(b)]
  7. #b is rotated array
  8. #print b
  9. s=int(raw_input())#element to find
  10. t=b.index(s)
  11. print t
  12.  
  13.  
Success #stdin #stdout 0.03s 6360KB
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https://ideone.com/S2Ixj
language:
Python (cpython 2.7.16)
created:
14 years ago
visibility:
public

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