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  1. #include <iostream>
  2. #include <cstdio>
  3. #include <cmath>
  4. using namespace std;
  5.  
  6. int main() {
  7. 	int n, a[100005], b;
  8. 	long long cnt;
  9. 	scanf("%d", &n);
  10. 	cnt=0;
  11. 	for(int i=0; i<n; i++) scanf("%d", &a[i]);
  12. 	for(int i=0; i<n; i++) {
  13. 		scanf("%d", &b);
  14. 		if(b>a[i]*2 || b<2) cnt--;
  15. 		else cnt+=pow(b, 2)/4;
  16. 	}
  17. 	printf("%lld\n", cnt);
  18. 	return 0;
  19. }
Success #stdin #stdout 0s 3612KB
comments (?)
stdin
copy 
1
1000000
1000000
stdout
copy 
250000000000
https://ideone.com/RQi4RR
language:
C++ (gcc 8.3)
created:
11 years ago
visibility:
public

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