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  1. f = @(x)sum(conv(x,1:3>0,'same'))
  2.  
  3. f([1,2,3,4,5])
Success #stdin #stdout 0.22s 103360KB
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Standard input is empty
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f =

@(x) sum (conv (x, 1:3 > 0, 'same'))

ans =  39
https://ideone.com/RB0j0J
language:
Octave (octave 4.4.1)
created:
7 years ago
visibility:
public

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