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  1. main(w,y,b,q){for(int f=0;f<5;f++){scanf("%d %d",&w,&y);for(b=0;b<w;b++){for(q=0;q<y;q++)printf("d f%d/du u%d%s",b,q,q<y-1?", ":"");printf("\n");}printf("\n");}}
Success #stdin #stdout 0s 2164KB
comments ()
stdin 
1 1
2 1 
2 2
1 2
3 3
stdout 
d f0/du u0

d f0/du u0
d f1/du u0

d f0/du u0, d f0/du u1
d f1/du u0, d f1/du u1

d f0/du u0, d f0/du u1

d f0/du u0, d f0/du u1, d f0/du u2
d f1/du u0, d f1/du u1, d f1/du u2
d f2/du u0, d f2/du u1, d f2/du u2
https://ideone.com/QpXYHa
language:
C (gcc 8.3)
created:
8 years ago
visibility:
public

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