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  1. #include <stdio.h>
  2. int main()
  3. {
  4.     int t,mx,i,sum;
  5.     char n[99999];
  6.     while(scanf("%s",&n)==1)
  7.     {
  8.         mx=0,sum=0;
  9.         for(i=0; n[i]!='\0'; i++)
  10.         {
  11.             if(n[i]>='0'&&n[i]<='9')
  12.                 t=n[i]-48;
  13.             else if(n[i]>='A'&&n[i]<='Z')
  14.                 t=n[i]-55;
  15.             else if(n[i]>='a'&&n[i]<='z')
  16.                 t=n[i]-61;
  17.             if(t>mx)
  18.                 mx=t;
  19.             sum=sum+t;
  20.         }
  21.         if(sum!=0)
  22.         {
  23.             for(i=mx; i<62; i++)
  24.                 if(sum%i==0)
  25.                 {
  26.                     printf("%d\n",i+1);
  27.                     break;
  28.                 }
  29.         if(i==62)
  30.             printf("such number is impossible!\n");
  31.          }
  32.         else
  33.             printf("2\n");
  34.     }
  35.     return 0;
  36. }
Success #stdin #stdout 0s 2276KB
comments (?)
stdin
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2
A
569569569551
2345
stdout
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3
11
such number is impossible!
8
https://ideone.com/Q7gFyx
language:
C (gcc 8.3)
created:
9 years ago
visibility:
public

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