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  1. pierwsze = [2,3,5,7,11,13,17,19,23,29]
  2.  
  3. def faktoryzuj(n) :
  4.     if(n>1) :
  5.         for x in pierwsze :
  6.             while n%x==0 :
  7.                 n = n/x
  8.                 yield x
  9.                 if n==1 :
  10.                     return
  11.  
  12. print([i for i in faktoryzuj(42)])
Success #stdin #stdout 0.08s 8880KB
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Standard input is empty
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[2, 3, 7]
https://ideone.com/PKqROF
language:
Python (cpython 2.7.16)
created:
11 years ago
visibility:
public

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