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  1. #include <iostream>
  2. #include <string>
  3.  
  4. using namespace std::literals;
  5.  
  6. int main() {
  7. 	std::string input = "depLookup88";
  8. 	auto pos = input.find_last_not_of("0123456789");
  9. 	std::string result = ( pos != std::string::npos ? input.substr(pos + 1) : ""s );
  10. 	std::cout << result;
  11. }
Success #stdin #stdout 0s 3228KB
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Standard input is empty
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88
https://ideone.com/OgqGua
language:
C++14 (gcc 8.3)
created:
9 years ago
visibility:
public

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