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  1. import java.util.*;
  2. import java.util.regex.*;
  3.  
  4. class Demo {
  5.     static public void main(String[] args) {
  6.         String[] arr = {
  7.             "Sales Tax 08/07 09/06 0.42",
  8.             "Sales Tax 02/07 02/14 -1.02"
  9.         };
  10.         Pattern pattern = Pattern.compile("^([a-zA-Z ]*) ([0-9]{2}/[0-9]{2} [0-9]{2}/[0-9]{2}) (-?[0-9]*\\.[0-9][0-9])");
  11.  
  12.         for (String str : arr) {
  13.             Matcher matcher = pattern.matcher(str);
  14.             if (matcher.find()) {
  15.                 System.out.println("String Name::"+matcher.group(0));
  16.                 System.out.println(matcher.group(1));
  17.                 System.out.println(matcher.group(2));
  18.                 System.out.println(matcher.group(3));
  19.                 System.out.println();
  20.             }
  21.         }
  22.     }
  23. }
  24.  
Success #stdin #stdout 0.07s 380224KB
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stdin
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Standard input is empty
stdout
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String Name::Sales Tax 08/07 09/06 0.42
Sales Tax
08/07 09/06
0.42

String Name::Sales Tax 02/07 02/14 -1.02
Sales Tax
02/07 02/14
-1.02
https://ideone.com/OZHE59
Illustration of answer to http://stackoverflow.com/questions/16737147/get-the-substring-using-regular-exrpression-in-java.
language:
Java (12.0.1)
created:
10 years ago
visibility:
secret

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