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  1. import re
  2. pattern = re.compile(r"\s*([^[\],]+)")
  3. string = '[ 1234, jack, 1987-09-02]'
  4. ret = pattern.findall(string)
  5. print(ret)
Success #stdin #stdout 0.01s 8968KB
comments ()
stdin 
Standard input is empty
stdout 
['1234', 'jack', '1987-09-02']
https://ideone.com/NZX1yc
language:
Python (cpython 2.7.16)
created:
8 years ago
visibility:
secret

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