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  1. def f(k,v):
  2.     dict={}#Создаем словарь
  3.     klen=len(k)# Колво ключей
  4.     vlen=len(v)# Колво значений
  5.     for i in range(min(klen,vlen)):
  6.         dict[k[i]]=v[i]#
  7.     if klen>vlen:#
  8.         for i in range(vlen,klen):#
  9.             dict[k[i]]=None#
  10.     return dict
  11. k=[1,2,3,4,5]
  12. v=[1,2,3]
  13. print(f(k,v))
  14. k=[1,2]
  15. v=[1,2,3]
  16. print(f(k,v))
  17. k=[1,2,3]
  18. v=[1,2,3]
  19. print(f(k,v))
Success #stdin #stdout 0.03s 9984KB
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{1: 1, 2: 2, 3: 3, 4: None, 5: None}
{1: 1, 2: 2}
{1: 1, 2: 2, 3: 3}
https://ideone.com/NHmbSc
language:
Python 3 (python  3.9.5)
created:
8 years ago
visibility:
public

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