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  1. double f(int n){double s=1,f=1;for(int i=0;i++<n;s+=f)f/=i;return s;}
  2. int main(){
  3. 	for(int i=0;i<20;i++){
  4. 		printf("%.10f\n",f(i));
  5. 	}
  6. }
Success #stdin #stdout 0s 2156KB
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stdin
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Standard input is empty
stdout
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1.0000000000
2.0000000000
2.5000000000
2.6666666667
2.7083333333
2.7166666667
2.7180555556
2.7182539683
2.7182787698
2.7182815256
2.7182818011
2.7182818262
2.7182818283
2.7182818284
2.7182818285
2.7182818285
2.7182818285
2.7182818285
2.7182818285
2.7182818285
https://ideone.com/MnPt3U
language:
C (gcc 8.3)
created:
7 years ago
visibility:
public

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