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  1. import re
  2. pattern = re.compile("(\{.+?\})")
  3. x = "{1.0 0b1 2006-01-01_12:34:56.789}{1.2345 0b100000 2006-01-01_12:34:56.789}"
  4. print(pattern.findall(x))
Success #stdin #stdout 0.02s 8688KB
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['{1.0 0b1 2006-01-01_12:34:56.789}', '{1.2345 0b100000 2006-01-01_12:34:56.789}']
https://ideone.com/LenM7E
language:
Python 3 (python  3.12)
created:
11 years ago
visibility:
public

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