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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int N, D1, D2, D3;
  5.     double aver;
  6.  
  7. scanf("%d", &N);
  8. D1 = N % 10;
  9. D2 = ((N - D1) / 10) % 10;
  10. D3 = (N - D1 - D2) / 100;
  11. aver = (double)(D1*100 + D2*10 + D3 + N) / 2;
  12.  
  13. printf("%lf", aver);
  14.  
  15. return 0;
  16. }
  17.  
Success #stdin #stdout 0s 2160KB
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https://ideone.com/LURvfG
Cast result into double to get accurate result
language:
C (gcc 8.3)
created:
10 years ago
visibility:
public

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