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  1. def group(items):
  2.   iterator = iter(items)
  3.   group = [next(iterator)]
  4.   result =[group]
  5.   for item in iterator:
  6.     (a, b), (c, d) = item, group[-1]
  7.     if a in (c, d) or b in (c, d):
  8.       group.append(item)
  9.     else:
  10.       group = [item]
  11.       result.append(group)
  12.  
  13.   return result
  14.  
  15. print(group([(1,2),(2,3),(3,4),(7,8),(8,9),(2,1),(2,3),(1,4)]))
Success #stdin #stdout 0.02s 8736KB
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Standard input is empty
stdout
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[[(1, 2), (2, 3), (3, 4)], [(7, 8), (8, 9)], [(2, 1), (2, 3)], [(1, 4)]]
https://ideone.com/L9obap
language:
Python 3 (python  3.12)
created:
10 years ago
visibility:
public

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