#include<stdio.h>
#include<math.h>
int main()
{
int test;
while(test--)
{
long long n,k,i;
scanf("%lld %lld",&n
,&k
); long long ans1,ans2,cnt;
double sum1,sum2;
cnt=ans1=ans2=0;
sum1=sum2=0.0;
if(((n*n)-(4*n*k))>=0)
{
sum1
=(n
+sqrt(((n
*n
)-(4*n
*k
))))/2.0; sum2
=(n
-sqrt(((n
*n
)-(4*n
*k
))))/2.0; //printf("%lld %lld\n",ans1,ans2);
for(i=ans2;i<n;i++)
{
if(i<=ans1)
cnt++;
}
}
else
}
return 0;
}
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