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  1. echo "18.11.2012" | awk -F"." '{t=mktime($3 " " $2 " " $1 " 00 00 00");
  2.      print strftime("%d %B %Y", t)}'
Success #stdin #stdout 0.03s 5312KB
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18 November 2012
https://ideone.com/Jmz77N
language:
Bash (bash 5.0.3)
created:
12 years ago
visibility:
public

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