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  1. #include<stdio.h>
  2. #include<math.h>
  3. int main()
  4. {long long t;
  5. long long c,n,b;
  6. scanf("%lld",&t);
  7. c=1;
  8. while(t--)
  9. {
  10. scanf("%lld",&n);
  11. b=(long long)(sqrt(n));
  12. if(b*b==n)
  13. printf("Case %lld: Yes\n",c);
  14. else
  15. printf("Case %lld: No\n",c);
  16. c++;
  17. }
  18. return 0;
  19. }
Success #stdin #stdout 0s 2252KB
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2
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stdout
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Case 1: Yes
Case 2: No
https://ideone.com/JeBAYn
language:
C (gcc 8.3)
created:
9 years ago
visibility:
public

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