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  1. def nao_comuns(a,b):
  2.     a_b = a+b # juntar as duas para percorrer todos os elementos
  3.     nao_comuns = []
  4.     for ele in a_b:
  5.         if ele not in a or ele not in b: # nao existe numa delas
  6.             nao_comuns.append(ele)
  7.     return nao_comuns
  8.  
  9. a = range(10) # [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
  10. b = range(0,20,2) # [0, 2, 4, 6, 8, 10, 12, 14, 16, 18]
  11. print nao_comuns(a,b) # [1, 3, 5, 7, 9, 10, 12, 14, 16, 18]
Success #stdin #stdout 0s 23352KB
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Standard input is empty
stdout
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[1, 3, 5, 7, 9, 10, 12, 14, 16, 18]
https://ideone.com/IqmVE3
language:
Python (cpython 2.7.16)
created:
7 years ago
visibility:
public

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