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#include <iostream>
#include <type_traits>
 
using namespace std;
 
int f()
{
	cout << "f" << endl;
	return 0;
}
 
struct F {
	int f()
	{
		cout << "F::f" << endl;
		return 0;
	}	
};
 
template <typename Function>
typename std::result_of<typename std::remove_reference<Function>::type>::type
call_f(Function&& f)
{
	return f();	
}
 
template <typename Function, class Class>
typename std::result_of<Function>::type
call_mf(Function&& f, Class* instance)
{
	return instance->*f();    
}
 
int main()
{
	call_f(f);
 
	F instance;
 
	call_fm(&F::f, &instance);
 
	return 0;
}
 

prog.cpp: In function ‘int main()’:
prog.cpp:36:10: error: no matching function for call to ‘call_f(int (&)())’
  call_f(f);
          ^
prog.cpp:36:10: note: candidate is:
prog.cpp:22:1: note: template<class Function> typename std::result_of<typename std::remove_reference< <template-parameter-1-1> >::type>::type call_f(Function&&)
 call_f(Function&& f)
 ^
prog.cpp:22:1: note:   template argument deduction/substitution failed:
prog.cpp: In substitution of ‘template<class Function> typename std::result_of<typename std::remove_reference< <template-parameter-1-1> >::type>::type call_f(Function&&) [with Function = int (&)()]’:
prog.cpp:36:10:   required from here
prog.cpp:22:1: error: no type named ‘type’ in ‘class std::result_of<int()>’
prog.cpp:40:26: error: ‘call_fm’ was not declared in this scope
  call_fm(&F::f, &instance);
                          ^

Standard output is empty