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  1. #include <stdio.h>
  2.  
  3. int  main(void)
  4. {
  5.   int  i, ch;
  6.   int  cnt[26] = {0};
  7.  
  8.   while(1) {
  9.     ch = getchar();
  10.     if (ch == EOF ) break;
  11.  
  12.     if ( ch >= 'a' && ch <= 'z'  )
  13.       cnt[  ch - 'a'  ]++;
  14.   }
  15.  
  16.   puts("文字の出現回数");
  17.   for (i = 0; i < 26; i++) {
  18.     putchar('a'+i) ;
  19.     printf(": %3d\n", cnt[i]);
  20.   }
  21.  
  22.   return (0);
  23. }
Success #stdin #stdout 0.01s 2728KB
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stdin
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Standard input is empty
stdout
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文字の出現回数
a:   0
b:   0
c:   0
d:   0
e:   0
f:   0
g:   0
h:   0
i:   0
j:   0
k:   0
l:   0
m:   0
n:   0
o:   0
p:   0
q:   0
r:   0
s:   0
t:   0
u:   0
v:   0
w:   0
x:   0
y:   0
z:   0
https://ideone.com/IBuI8
language:
C++ (gcc 8.3)
created:
12 years ago
visibility:
secret

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