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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. volatile double x=120;
  5.  
  6. int main()
  7.   {
  8.    if(x*(1/10.0)!=x/10.0) cout<<"nie jest to dobry sposób"<<endl;
  9.    return 0;
  10.   }
Success #stdin #stdout 0s 3340KB
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Standard input is empty
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nie jest to dobry sposób
https://ideone.com/HkmKK4
language:
C++ (gcc 8.3)
created:
9 years ago
visibility:
public

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