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  1. #include<bits/stdc++.h>
  2. int days[13]={0,31,28,31,30,31,30,31,31,30,31,30,31},pre[13];
  3. int year,initial,n,month,day;
  4. bool is_leap_year(){ //判斷是否是閏年
  5. 	if(!(year%400))return true;
  6. 	if(!(year%100))return false;
  7. 	if(!(year%4))return true;
  8. 	return false;
  9. }
  10. int calc(){
  11. 	if(month<1||month>12)return -1;
  12. 	if(day<1||day>days[month]+(is_leap_year()&&month==2))return -2;
  13. 	int sum=pre[month-1]+day; //sum=這年的第幾天
  14. 	if(is_leap_year()&&month>2)sum++;
  15. 	return (sum-1+initial)%7;
  16. }
  17. main(){
  18. 	for(int i=1;i<13;i++)
  19. 		pre[i]=pre[i-1]+days[i]; 
  20.     printf("輸入年份跟1/1是星期幾\n");
  21.     scanf("%d%d",&year,&initial);
  22.     printf("輸入有幾組日期要算(n=1~10))\n");
  23.     scanf("%d",&n);
  24.     printf("輸入日期\n");
  25.     while(n--){
  26.     	scanf("%d%d",&month,&day);
  27.     	printf("%d\n",calc());
  28. 	}
  29. 	return 0;
  30. }
Success #stdin #stdout 0s 3416KB
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輸入年份跟1/1是星期幾
輸入有幾組日期要算(n=1~10))
輸入日期
https://ideone.com/HBq15Z
language:
C++14 (gcc 8.3)
created:
7 years ago
visibility:
public

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