#include <iostream>
#include <bits/stdc++.h>
using namespace std;
void call( int m,int n,int ** a)
{
for ( int i= 0 ; i< m; i++ )
{
for ( int j= 0 ; j< n; j++ )
cout << a[ i] [ j] ;
cout << endl;
}
}
int main( )
{
// your code goes here
int m,n;
cin >> m>> n;
int a[ m] [ n] ;
for ( int i= 0 ; i< m; i++ )
for ( int j= 0 ; j< n; j++ )
cin >> a[ i] [ j] ;
call( m,n,a) ;
return 0 ;
}
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compilation info
prog.cpp: In function ‘int main()’:
prog.cpp:26:14: error: cannot convert ‘int (*)[n]’ to ‘int**’ for argument ‘3’ to ‘void call(int, int, int**)’
call(m,n,a);
^
stdout