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#include<stdio.h> 
#include<string.h>
void main() 
{
	char string[50];
	int flag,count=o;
 
	printf("The grammar is: S->aS, S->Sb, S->ab\n");
	printf("Enter the string to be checked:\n");
	gets(string);
	if(string[0]=='a') 
	{
		flag=0;
		for (count=1;string[count-1]!='\0';count++) 
		{
			if(string[count]=='b') 
			{
				flag=1;
				continue;
			} 
			else if((flag==1)&&(string[count]=='a')) 
			{
				printf("The string does not belong to the specified grammar");
				break;
			} 
			else if(string[count]=='a')
			{
			    continue; 
			}
			else if(flag==1)&&(string[count]='\0')) 
			{
				printf("String accepted…..!!!!");
				break;
			} 
			else 
			{
				printf("String not accepted");
			}
		}
	}
 
}
 

prog.c:3:6: warning: return type of ‘main’ is not ‘int’ [-Wmain]
 void main()
      ^~~~
prog.c: In function ‘main’:
prog.c:6:17: error: ‘o’ undeclared (first use in this function)
  int flag,count=o;
                 ^
prog.c:6:17: note: each undeclared identifier is reported only once for each function it appears in
prog.c:10:2: warning: implicit declaration of function ‘gets’ [-Wimplicit-function-declaration]
  gets(string);
  ^~~~
prog.c:30:22: error: expected identifier before ‘(’ token
    else if(flag==1)&&(string[count]='\0'))
                      ^
prog.c:30:4: warning: this ‘else’ clause does not guard... [-Wmisleading-indentation]
    else if(flag==1)&&(string[count]='\0'))
    ^~~~
prog.c:30:42: note: ...this statement, but the latter is misleadingly indented as if it is guarded by the ‘else’
    else if(flag==1)&&(string[count]='\0'))
                                          ^
prog.c:30:42: error: expected statement before ‘)’ token
prog.c:35:4: error: ‘else’ without a previous ‘if’
    else
    ^~~~

Standard output is empty