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  1. #include <iostream>
  2. #include<math.h>
  3. #include <iomanip> 
  4. using namespace std;
  5. int n,m,q,ph;
  6. template<typename Type>
  7.  
  8. int cosh(Type **a, const int n, const int m,int q){
  9.   int i,j,unnul,k,f; int tmp; bool p; Type jey;
  10.   cout<<"\n";
  11.   for (j = 0; j < m; j++)  
  12.     for (i = 0; i < n; i++) 
  13.     if (a[i,j]==0) {cout<<j+1; i=n; j=n;}
  14. /*f= n*m; 
  15.   Type *a1 = new Type [f];
  16.    unnul = 0; k = 0;
  17.   for (i = 0; i < n; i++) { 
  18.     for (j = 0; j < m; j++) 
  19.     {if (a[i][j] == 0) k++;}
  20.     if (k==0) unnul++; k = 0;}
  21.  
  22.   k=0;
  23. for (i = 0; i < n; i++)  
  24.     for (j = 0; j < m; j++) 
  25.     {a1[k]=a[i][j]; k++;}
  26.  
  27. for (i=0; i<f; i++)
  28.     for (j=0; j<f; j++)
  29.         if (a1[j] > a1[j+1]) 
  30. {                
  31.            tmp = a1[j];
  32.            a1[j] = a1[j+1];
  33.            a1[j+1] = tmp;
  34. }
  35. for(i=f; i>=0; i--) 
  36. { 
  37. if(a1[i] == a1[i-1]) 
  38. { 
  39. jey = a1[i]; 
  40. break; 
  41. } 
  42. } 
  43. cout<<unnul<<".";
  44. for(i = 1; i<=ph;i++)
  45. cout<<"0";
  46. cout<<" "<< fixed << setprecision(ph) << jey<<endl;
  47. ph +=2;*/
  48. return 0;
  49. }
  50.  
  51. int m1( )
  52. {
  53.   int i,j,unnul,k,f; int tmp; bool p;
  54.   int **a = new int *[n];
  55.   ph = 0;
  56.     for (i = 0; i < n; i++) a[i] = new int [m];
  57.   for (i = 0; i < n; i++)  
  58.     for (j = 0; j < m; j++) 
  59.     cin >> a[i][j];
  60.     q=0;
  61.    cosh(a,n,m,q);
  62.  
  63.     return 0;
  64. }
  65.  
  66. int m2( )
  67. {
  68.   int i,j,unnul,k,f; int tmp; bool p;
  69.   float **a = new float *[n];
  70.  
  71.     for (i = 0; i < n; i++) a[i] = new float [m];
  72.   for (i = 0; i < n; i++)  
  73.     for (j = 0; j < m; j++) 
  74.     cin >> a[i][j];
  75.     q=1;
  76.    cosh(a,n,m,q);
  77.  
  78.     return 0;
  79. }
  80.  
  81. int m3( )
  82. {
  83.   int i,j,unnul,k,f; int tmp; bool p;
  84.   float **a = new float *[n];
  85.  
  86.     for (i = 0; i < n; i++) a[i] = new float [m];
  87.   for (i = 0; i < n; i++)  
  88.     for (j = 0; j < m; j++) 
  89.     cin >> a[i][j];
  90.     q=2;
  91.    cosh(a,n,m,q);
  92.  
  93.     return 0;
  94. }
  95.  
  96. int main()
  97. {
  98.       cin >> n >> m;
  99.       m1(); m2(); m3();
  100.       return 0;
  101. }
  102.  
Success #stdin #stdout 0s 15240KB
comments (?)
stdin
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3 4
-2 0 4 7
7 -8 -1 5
0 -3 4 1
1.849 -3 0.01 2
-0.05 9 2 -1.555
0 2.12 9 1
0.1234 0 -7.602 -8.54
1 4.00005 1.99 -2
6.02207 1 -1 0
stdout
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https://ideone.com/G86NZz
language:
C++ (gcc 8.3)
created:
7 years ago
visibility:
public

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