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  1. #include<stdio.h>
  2. #include<math.h>
  3. #include<string.h>
  4. typedef long long ll;
  5. ll at[1000005];
  6. ll prime(ll n)
  7. {
  8. 	ll i,count=0;
  9. 	while(n%2==0)
  10. 	{
  11. 		count++;
  12. 		n=n/2;
  13. 	}
  14. 	if(count>at[2])
  15. 	at[2]=count;
  16. 	for(i=3;i<=sqrt(n);i=i+2)
  17. 	{
  18. 		count=0;
  19. 		while(n%i==0)
  20. 		{
  21. 			count++;
  22. 			n=n/i;
  23. 		}
  24. 		if(count>at[i])
  25. 		at[i]=count;
  26. 	}
  27. 	if(n>2)
  28. 	{
  29. 		if(at[n]==0)
  30. 		at[n]=1;
  31. 	}
  32. }
  33. int main()
  34. {
  35. 	ll t,n,i,k,count;
  36. 	ll ar[100005];
  37. 	scanf("%lld",&t);
  38. 	while(t--)
  39. 	{
  40. 		for(i=0;i<1000005;i++)
  41. 		at[i]=0;
  42. 		count=0;
  43. 		scanf("%lld",&n);
  44. 		for(i=0;i<n;i++)
  45. 		scanf("%lld",&ar[i]);
  46. 		for(i=0;i<n;i++)
  47. 		prime(ar[i]);
  48. 		for(i=0;i<=1000005;i++)
  49. 		count=count+at[i];
  50. 	    printf("%lld\n",count);
  51. 	}
  52. 	return 0;
  53.  
  54. }
Success #stdin #stdout 0s 11928KB
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https://ideone.com/G6t0fX
language:
C++ (gcc 8.3)
created:
9 years ago
visibility:
secret

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