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  1. d='?":\x10;8/\x08&0%\x01\'!\x12\x0e\x0f\x05+\n1>\x06\x16.$\x0b,\x1b\x133*'
  2. k=lambda(l):'\n'.join("{0:06b}".format(l)).replace('1','#######').replace('0','### ###')
  3. def t(a):
  4.  j=a+a%2-1;m=ord(d[j/2]);b=k(m);r=b[::-1];print b,j,'\n\n',r if r!=b else k(63-m),j+1
  5.  
  6. t(input())
Success #stdin #stdout 0.01s 9016KB
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stdin
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16
stdout
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### ###
### ###
#######
### ###
### ###
### ### 15 

### ###
### ###
### ###
#######
### ###
### ### 16
https://ideone.com/FeK1rK
Willem's I-Ching code in Python 2
language:
Python (cpython 2.7.16)
created:
8 years ago
visibility:
public

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