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  1. def reverse_factorial(n):
  2.     div = 1
  3.     while True:
  4.         if n <1:
  5.             return 'none'
  6.         elif n == 1:
  7.             return str(div) + '!'
  8.         n /= div
  9.         div += 1
  10.  
  11. print(reverse_factorial(100))
  12. print(reverse_factorial(120))
  13. print(reverse_factorial(1))
  14. print(reverse_factorial(0))
Success #stdin #stdout 0.01s 9992KB
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6!
1!
none
https://ideone.com/EpTeGq
language:
Python 3 (python  3.9.5)
created:
7 years ago
visibility:
public

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