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  1. #!/bin/bash
  2.  
  3. declare -rgA arr=([1234]=A1 [1235]=A2 [2345]=B1 [5678]=C2 [2346]=D5)
  4.  
  5. i=0
  6. for chip in "${!arr[@]}"
  7. do
  8.     echo " var $((i++)) is $chip and version is ${arr[$chip]}"
  9. done
  10.  
  11. bash --version
  12.  
Success #stdin #stdout 0s 19640KB
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stdin
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Standard input is empty
stdout
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 var 0 is 2345 and version is B1
 var 1 is 2346 and version is D5
 var 2 is 1234 and version is A1
 var 3 is 1235 and version is A2
 var 4 is 5678 and version is C2
GNU bash, version 4.4.11(1)-release (x86_64-pc-linux-gnu)
Copyright (C) 2016 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://g...content-available-to-author-only...u.org/licenses/gpl.html>

This is free software; you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
https://ideone.com/Ef9T9P
http://stackoverflow.com/questions/43367187/regex-usage-in-shell-script#43367420
language:
Bash (bash 5.0.3)
created:
7 years ago
visibility:
public

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