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  1. a = [1, 4, 45, 6, 10,0, 8]
  2. x = 10
  3. b = []
  4. for i in range(100):
  5.     b.append(0)
  6. for i in a:
  7.     if(b[x-i+1] == 1):
  8.         print("pair:")
  9.         print(i)
  10.         print(x-i)
  11.     b[i+1] = 1
  12.  
Success #stdin #stdout 0.03s 9440KB
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stdin
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Standard input is empty
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pair:
6
4
pair:
0
10
https://ideone.com/E6v3sE
Given an array A[] and a number x, check for pair in A[] with sum as x
language:
Python 3 (python  3.9.5)
created:
9 years ago
visibility:
public

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