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  1. #include<stdio.h>
  2. #include<string.h>
  3. #include<stdlib.h>
  4.  
  5.  
  6. char a[100],a1[100],a2[100],a3[100];
  7.  
  8. int main() 
  9. { 
  10.    int i,c1=0,c2=0,c3=0,i1,i2,len,j1,j,t,x;
  11.    scanf("%d",&t); 
  12.    getchar(); // here to ignore enter hit.
  13. for(x=0;x<t;x++)
  14. {
  15.     getchar();
  16.     gets(a);
  17.     len=strlen(a);
  18.     for(i=0;i<len;i++)
  19.     {
  20.         if(a[i]=='+')
  21.             i1=i;
  22.         if(a[i]=='=')
  23.             i2=i;
  24.     }
  25.     for(j=0;j<i1;j++)
  26.     {
  27.         a1[j]=a[j];
  28.         c1++;
  29.         if(a[j]=='m')
  30.             j1=1;
  31.     } 
  32.     for(j=i1+1;j<i2;j++)
  33.     {
  34.         a2[j-(i1+1)]=a[j];
  35.         c2++;
  36.         if(a[j]=='m')
  37.             j1=2; 
  38.     } 
  39.     a2[c2]='\0'; 
  40.     for(j=i2+1;j<len;j++) 
  41.     {
  42.         a3[j-(i2+1)]=a[j];
  43.         c3++;
  44.         if(a[j]=='m')
  45.         j1=3;
  46.     } 
  47.     a3[c3]='\0';
  48.  
  49.     a1[c1]='\0';
  50.     switch(j1) 
  51.     { 
  52.         case 1: 
  53.             len=atoi(a3)-atoi(a2);
  54.             printf("%d + %s = %s\n",len,a2,a3); // spaces between each object.
  55.             break;
  56.         case 2:
  57.             len=atoi(a3)-atoi(a1);
  58.             printf("%s + %d = %s\n",a1,len,a3);
  59.             break;
  60.         case 3: 
  61.             len=atoi(a1)+atoi(a2); 
  62.             printf("%s + %s = %d\n",a1,a2,len); 
  63.             break; 
  64.         default : ;    
  65.     }
  66.     c1=0; 
  67.     c2=0; 
  68.     c3=0;
  69.     }
  70. return 0;
  71. }
Success #stdin #stdout 0s 2900KB
comments (?)
stdin
copy 
3
23 + 47 = machula

3247 + 5machula2 = 3749

machula13 + 75425 = 77038
stdout
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3  +  47  = 50
3247  + 502 =  3749
1613 +  75425  =  77038
https://ideone.com/DwuWEA
language:
C++ (gcc 8.3)
created:
10 years ago
visibility:
secret

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