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  1. #include <iostream>
  2. #include <cmath>
  3. #include <vector>
  4. #include <cassert>
  5.  
  6. typedef std::vector<double> Points;
  7.  
  8. double l(const Points &points)
  9. {
  10.     double sum = 0;
  11.     for(int i = 0; i < points.size(); ++i)
  12.         sum += (points[i]*points[i]);
  13.     return std::sqrt(sum);
  14. };
  15. Points n(Points points)
  16. {
  17.     double length = l(points);
  18.     for(int i = 0; i < points.size(); ++i)
  19.         points[i] /= length;
  20.     return points;
  21. };
  22. double d(const Points &a, const Points &b)
  23. {
  24.     double sum = 0;
  25.     assert(a.size() == b.size());
  26.     for(int i = 0; i < a.size(); ++i)
  27.         sum += (a[i]*b[i]);
  28.     return sum;
  29. };
  30.  
  31. int main()
  32. {
  33.     int N = 0;
  34.     std::cin >> N;
  35.  
  36.     std::vector<Points> P;
  37.     for(;N > 0; --N)
  38.     {
  39.         int A = 0;
  40.         double R = 0;
  41.         std::cin >> A;
  42.  
  43.         Points points;
  44.         for(;A > 0; --A)
  45.         {
  46.             std::cin >> R;
  47.             points.push_back(R);
  48.         }
  49.         P.push_back(points);
  50.     }
  51.  
  52.     std::cin >> N;
  53.     std::vector<Points > O;
  54.     for(;N > 0; --N)
  55.     {
  56.         Points o;
  57.         char C = 0;
  58.         int I = 0;
  59.         std::cin >> C >> I;
  60.  
  61.         if(C == 'l')
  62.             o.push_back(l(P[I]));
  63.         else if(C == 'n')
  64.         {
  65.             Points p = n(P[I]);
  66.             for(int i = 0; i < p.size(); ++i)
  67.                 o.push_back(p[i]);
  68.         }
  69.         else if(C == 'd')
  70.         {
  71.             int I2 = 0;
  72.             std::cin >> I2;
  73.             o.push_back(d(P[I], P[I2]));
  74.         }
  75.         O.push_back(o);
  76.     }
  77.  
  78.     std::cout << std::endl;
  79.     for(int i = 0; i < O.size(); ++i)
  80.     {
  81.         for(int e = 0; e < O[i].size(); ++e)
  82.             std::cout << O[i][e] << " ";
  83.         std::cout << std::endl;
  84.     }
  85.     return 0;
  86. }
Success #stdin #stdout 0s 3040KB
comments (?)
stdin
copy 
5
2 1 1
2 1.2 3.4
3 6.78269 6.72 6.76312
4 0 1 0 1
7 84.82 121.00 467.05 142.14 592.55 971.79 795.33
7
l 0
l 3
l 4
n 1
n 2
n 3
d 0 1
stdout
copy 
1.41421 
1.41421 
1479.26 
0.33282 0.94299 
0.579689 0.574332 0.578017 
0 0.707107 0 0.707107 
4.6
https://ideone.com/DruIPp
language:
C++ (gcc 8.3)
created:
10 years ago
visibility:
public

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