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  1. #include <stdio.h>
  2.  
  3. double my_exp_n (double x, int degree)
  4. {
  5.     int i;
  6.     double exp_val=0.0;
  7.     double x_div_l=1.0;
  8.  
  9.     for (i=0;i<=degree;++i)
  10.     {
  11.         exp_val += x_div_l;
  12.         x_div_l *= x / (i+1);
  13.  
  14.         printf("exp_%d (%.2f) = %e\n", i, x, exp_val);
  15.     }
  16.  
  17.     return exp_val;
  18. }
  19.  
  20. int main()
  21. {
  22.     my_exp_n (1, 10);
  23.     return 0;   
  24. }
Success #stdin #stdout 0.01s 1720KB
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stdin
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Standard input is empty
stdout
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exp_0 (1.00) = 1.000000e+00
exp_1 (1.00) = 2.000000e+00
exp_2 (1.00) = 2.500000e+00
exp_3 (1.00) = 2.666667e+00
exp_4 (1.00) = 2.708333e+00
exp_5 (1.00) = 2.716667e+00
exp_6 (1.00) = 2.718056e+00
exp_7 (1.00) = 2.718254e+00
exp_8 (1.00) = 2.718279e+00
exp_9 (1.00) = 2.718282e+00
exp_10 (1.00) = 2.718282e+00
https://ideone.com/C4Mjnz
language:
C (gcc 8.3)
created:
12 years ago
visibility:
public

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