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  1. f = [[1, 'nan'], [2, 'nan', 'nan'], [1, 3]]
  2. ef = []
  3.  
  4. for x in f:
  5.     found = False
  6.     for pos, e in enumerate(x):
  7.         if e == 'nan':
  8.             x[pos] = 1
  9.             found = True
  10.     ef.append(1 if found else 0)
  11.  
  12. print f, ef
Success #stdin #stdout 0s 9024KB
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Standard input is empty
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[[1, 1], [2, 1, 1], [1, 3]] [1, 1, 0]
https://ideone.com/BDMjy8
language:
Python (cpython 2.7.16)
created:
7 years ago
visibility:
public

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