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  1. #include <stdio.h>
  2.  
  3. double solve(const double a, const double n) {
  4.     double temp = a;
  5.     double result = 1.0 / a;
  6.     for (int i = 1; i <= n; i += 1) {
  7.         temp *= (a + i);
  8.         result += 1.0 / temp;
  9.     }
  10.     return result;
  11. }
  12.  
  13. int main() {
  14.     double a = 1, n = 2;
  15.     printf("%.3f\n", solve(a, n));
  16. }
  17.  
Success #stdin #stdout 0s 2168KB
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https://ideone.com/ArHkgC
language:
C (gcc 8.3)
created:
8 years ago
visibility:
public

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