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  1. l=lambda n:sum(len(`i`)for i in range(1,n+1))
  2.  
  3. def factors(n):    
  4.     return sorted(list(set(reduce(list.__add__, 
  5.     ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0)))))
  6.  
  7. n=99
  8. print l(n), factors(l(n))
Success #stdin #stdout 0.01s 9016KB
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Standard input is empty
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189 [1, 3, 7, 9, 21, 27, 63, 189]
https://ideone.com/AkejPS
Length of concatenated numbers, and the factors of the result
language:
Python (cpython 2.7.16)
created:
8 years ago
visibility:
secret

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