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  1. # your code goes here
  2.  
  3. def A( n ):
  4. 	if n==1:
  5. 		return 1
  6. 	else:
  7. 		return 10**(n-1)+9*A(n-1)
  8.  
  9. print A(6)
Success #stdin #stdout 0.01s 7896KB
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468559
https://ideone.com/AcV9PR
http://m...content-available-to-author-only...e.com/questions/669737/how-many-numbers-1-000-000-have-the-digit-2
language:
Python (cpython 2.7.16)
created:
10 years ago
visibility:
public

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