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  1.  
  2.  
  3. #include<stdio.h>
  4.  
  5. int main(){
  6.  
  7.   long n,m,i=0,k=0,j=0;
  8.  
  9.   long long A[100000];
  10.  
  11.    char a;
  12.  
  13.   scanf("%ld%ld",&n,&m);
  14.  
  15.   for(i=0;i<n;i++){
  16.  
  17.      scanf("%ld",A+i);
  18.  
  19.   }
  20.  
  21.    i=0;j=n-1;
  22.  
  23. while(m-- > 0){
  24.  
  25.           fflush(stdin);
  26.    scanf("%c%ld",&a,&k);
  27.  
  28.              if(a== 'C'){
  29.                       i=(i+k)%n;
  30.                       j=(j+k)%n;
  31.                      // printf("i=%ld j=%ld\n",i,j);
  32.              }
  33.              else if (a=='A'){
  34.                      i=(i+n-k)%n;
  35.                      j=(j+n-k)%n;
  36.                                            //    printf("i=%ld j=%ld\n",i,j);
  37.              }
  38.              else{
  39.                      // printf("i=%ld j=%ld\n",i,j);
  40.                       printf("%lld\n",A[(i+k-1)%n]);
  41.              }
  42.  
  43.  
  44.  
  45.    //printf("The value of m:%ld\n",m);
  46. }
  47.  
  48. //getch(); 
  49. return 0;
  50.  
  51. }
  52.  
Success #stdin #stdout 0s 2716KB
comments (?)
stdin
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5 10
5 6 1 2 5
R 5
C 1
A 3
A 5
R 4
R 1
A 5
R 1
R 1
R 3
stdout
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9
5
5
6
5
1
6
https://ideone.com/9R2eZy
language:
C (gcc 8.3)
created:
9 years ago
visibility:
public

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