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  1. a = [4,3,4,7,3,9]
  2. s = 0
  3. for i in a:
  4.     s = s ^ i
  5. c = 1
  6. while(1):
  7.     if(s&1 == 1):
  8.         break
  9.     else:
  10.         s = s>>1
  11.         c = c + 1
  12. n = c**2
  13. b = []
  14. d = []
  15. for i in a:
  16.     t = i^n
  17.     if((t>>(c-1) & 1) == 1):
  18.         b.append(i)
  19.     else:
  20.         d.append(i)
  21. e = 0
  22. f = 0
  23. for i in b:
  24.     e = e ^ i
  25. print(e)
  26. for i in d:
  27.     f = f ^ i
  28. print(f)
  29.  
Success #stdin #stdout 0.11s 10104KB
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https://ideone.com/8oJcXR
Find the two non-repeating elements in an array of repeating elements
language:
Python 3 (python  3.9.5)
created:
9 years ago
visibility:
public

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