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  1. SELECT *
  2. FROM mitarbeiter m
  3. join
  4. (SELECT mnr as x, count(thema) as ANZAHL FROM
  5. (SELECT k.mnr, b.thema FROM
  6. kundenbetreuer k right
  7. join betreut b on
  8. (k.mnr = b.betreuer)
  9. GROUP BY k.mnr, b.thema)
  10. GROUP BY mnr HAVING anzahl =
  11. (SELECT max(t) FROM (SELECT count(thema) as t from betreut group by betreuer, thema))
  12. on (m.mnr = x)
Success #stdin #stdout 0s 3008KB
stdin
Standard input is empty
stdout
Standard output is empty