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  1. #include <stdio.h>
  2.  
  3. f(p,n)int*p;{n>1?*p<p[1]?*p=p[1]:f(p+1,n-1):0;}
  4.  
  5. int main(void)
  6. {
  7. 	int l[5] = { 3, 1, 4, -1, 2 };
  8. 	f(l,5);
  9. 	for(int i=0;i<5;i++) printf("%d ",l[i]);
  10. 	return 0;
  11. }
  12.  
Success #stdin #stdout 0s 9432KB
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stdin
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Standard input is empty
stdout
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3 4 4 -1 2
https://ideone.com/83HJqN
language:
C (gcc 8.3)
created:
7 years ago
visibility:
public

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