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  1. #include <stdio.h>
  2. #include <string.h>
  3. #include <time.h>
  4.  
  5. typedef unsigned uint;
  6. typedef unsigned long long uint64;
  7.  
  8. struct tm* SecondsSinceEpochToDateTime(struct tm* pTm, uint64 SecondsSinceEpoch)
  9. {
  10.   uint64 sec;
  11.   uint quadricentennials, centennials, quadrennials, annuals/*1-ennial?*/;
  12.   uint year, leap;
  13.   uint yday, hour, min;
  14.   uint month, mday, wday;
  15.   static const uint daysSinceJan1st[2][13]=
  16.   {
  17.     {0,31,59,90,120,151,181,212,243,273,304,334,365}, // 365 days, non-leap
  18.     {0,31,60,91,121,152,182,213,244,274,305,335,366}  // 366 days, leap
  19.   };
  20. /*
  21.   400 years:
  22.  
  23.   1st hundred, starting immediately after a leap year that's a multiple of 400:
  24.   n n n l  \
  25.   n n n l   } 24 times
  26.   ...      /
  27.   n n n l /
  28.   n n n n
  29.  
  30.   2nd hundred:
  31.   n n n l  \
  32.   n n n l   } 24 times
  33.   ...      /
  34.   n n n l /
  35.   n n n n
  36.  
  37.   3rd hundred:
  38.   n n n l  \
  39.   n n n l   } 24 times
  40.   ...      /
  41.   n n n l /
  42.   n n n n
  43.  
  44.   4th hundred:
  45.   n n n l  \
  46.   n n n l   } 24 times
  47.   ...      /
  48.   n n n l /
  49.   n n n L <- 97'th leap year every 400 years
  50. */
  51.  
  52.   // Re-bias from 1970 to 1601:
  53.   // 1970 - 1601 = 369 = 3*100 + 17*4 + 1 years (incl. 89 leap days) =
  54.   // (3*100*(365+24/100) + 17*4*(365+1/4) + 1*365)*24*3600 seconds
  55.   sec = SecondsSinceEpoch + 11644473600;
  56.  
  57.   wday = (uint)((sec / 86400 + 1) % 7); // day of week
  58.  
  59.   // Remove multiples of 400 years (incl. 97 leap days)
  60.   quadricentennials = (uint)(sec / 12622780800ULL); // 400*365.2425*24*3600
  61.   sec %= 12622780800ULL;
  62.  
  63.   // Remove multiples of 100 years (incl. 24 leap days), can't be more than 3
  64.   // (because multiples of 4*100=400 years (incl. leap days) have been removed)
  65.   centennials = (uint)(sec / 3155673600ULL); // 100*(365+24/100)*24*3600
  66.   if (centennials > 3)
  67.   {
  68.     centennials = 3;
  69.   }
  70.   sec -= centennials * 3155673600ULL;
  71.  
  72.   // Remove multiples of 4 years (incl. 1 leap day), can't be more than 24
  73.   // (because multiples of 25*4=100 years (incl. leap days) have been removed)
  74.   quadrennials = (uint)(sec / 126230400); // 4*(365+1/4)*24*3600
  75.   if (quadrennials > 24)
  76.   {
  77.     quadrennials = 24;
  78.   }
  79.   sec -= quadrennials * 126230400ULL;
  80.  
  81.   // Remove multiples of years (incl. 0 leap days), can't be more than 3
  82.   // (because multiples of 4 years (incl. leap days) have been removed)
  83.   annuals = (uint)(sec / 31536000); // 365*24*3600
  84.   if (annuals > 3)
  85.   {
  86.     annuals = 3;
  87.   }
  88.   sec -= annuals * 31536000ULL;
  89.  
  90.   // Calculate the year and find out if it's leap
  91.   year = 1601 + quadricentennials * 400 + centennials * 100 + quadrennials * 4 + annuals;
  92.   leap = !(year % 4) && (year % 100 || !(year % 400));
  93.  
  94.   // Calculate the day of the year and the time
  95.   yday = sec / 86400;
  96.   sec %= 86400;
  97.   hour = sec / 3600;
  98.   sec %= 3600;
  99.   min = sec / 60;
  100.   sec %= 60;
  101.  
  102.   // Calculate the month
  103.   for (mday = month = 1; month < 13; month++)
  104.   {
  105.     if (yday < daysSinceJan1st[leap][month])
  106.     {
  107.       mday += yday - daysSinceJan1st[leap][month - 1];
  108.       break;
  109.     }
  110.   }
  111.  
  112.   // Fill in C's "struct tm"
  113.   memset(pTm, 0, sizeof(*pTm));
  114.   pTm->tm_sec = sec;          // [0,59]
  115.   pTm->tm_min = min;          // [0,59]
  116.   pTm->tm_hour = hour;        // [0,23]
  117.   pTm->tm_mday = mday;        // [1,31]  (day of month)
  118.   pTm->tm_mon = month - 1;    // [0,11]  (month)
  119.   pTm->tm_year = year - 1900; // 70+     (year since 1900)
  120.   pTm->tm_wday = wday;        // [0,6]   (day since Sunday AKA day of week)
  121.   pTm->tm_yday = yday;        // [0,365] (day since January 1st AKA day of year)
  122.   pTm->tm_isdst = -1;         // daylight saving time flag
  123.  
  124.   return pTm;
  125. }
  126.  
  127. int main(void)
  128. {
  129.   struct tm t;
  130.   time_t tt;
  131.   printf("%s",   asctime(SecondsSinceEpochToDateTime(&t, -1)));
  132.   printf("%s",   asctime(gmtime((tt = 0, &tt))));
  133.   printf("%s",   asctime(SecondsSinceEpochToDateTime(&t, 0)));
  134.   printf("%s\n", asctime(SecondsSinceEpochToDateTime(&t, 1)));
  135.  
  136.   printf("%s",   asctime(SecondsSinceEpochToDateTime(&t, 946684799)));
  137.   printf("%s",   asctime(SecondsSinceEpochToDateTime(&t, 946684799+1)));
  138.   printf("%s\n", asctime(SecondsSinceEpochToDateTime(&t, 946684799+2)));
  139.  
  140.   printf("%s",   asctime(SecondsSinceEpochToDateTime(&t, 978307199)));
  141.   printf("%s",   asctime(SecondsSinceEpochToDateTime(&t, 978307199+1)));
  142.   printf("%s\n", asctime(SecondsSinceEpochToDateTime(&t, 978307199+2)));
  143.  
  144.   printf("%s",   asctime(SecondsSinceEpochToDateTime(&t, tt = time(0))));
  145.   printf("%s",   asctime(gmtime(&tt)));
  146.   return 0;
  147. }
  148.  
Success #stdin #stdout 0.01s 1808KB
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stdout
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Wed Dec 31 23:59:59 1969
Thu Jan  1 00:00:00 1970
Thu Jan  1 00:00:00 1970
Thu Jan  1 00:00:01 1970

Fri Dec 31 23:59:59 1999
Sat Jan  1 00:00:00 2000
Sat Jan  1 00:00:01 2000

Sun Dec 31 23:59:59 2000
Mon Jan  1 00:00:00 2001
Mon Jan  1 00:00:01 2001

Mon Jun 25 11:39:42 2012
Mon Jun 25 11:39:42 2012
https://ideone.com/7BADb
language:
C (gcc 8.3)
created:
11 years ago
visibility:
public

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