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  1. #include<iostream>
  2. #include<algorithm>
  3. #include<unordered_map>
  4. #include<array>
  5. #include<list>
  6.  
  7. template < typename T1 >
  8. std::unordered_map< int, int > count_frequency( T1 first, T1 last )
  9. {
  10.     std::unordered_map< int, int > temp_unordered_map;
  11.     auto temp_unordered_map_end = std::end( temp_unordered_map );
  12.     while( first != last )
  13.     {
  14.         auto it_temp_unordered_map = temp_unordered_map.find( *first );
  15.         if( it_temp_unordered_map == temp_unordered_map_end )
  16.         {
  17.             temp_unordered_map.emplace( *first, 1 );                       
  18.         }
  19.         else
  20.         {
  21.             ++( it_temp_unordered_map->second );
  22.         }
  23.         ++first;
  24.     }
  25.     return temp_unordered_map;
  26. }
  27.  
  28. template < typename T1, typename T2 >
  29. bool is_permutation( const T1 first1, const T1 last1, const T2 first2, const T2 last2 )
  30. {   
  31.     return count_frequency( first1, last1 )== count_frequency( first2, last2 );
  32.  
  33. }
  34.  
  35. int main()
  36. {     
  37.     const std::array< int, 5> array1 { { 1, 3, 2, 4, 5 } };
  38.     const std::array<int,4> array2 { { 1, 2, 4, 3 } };
  39.  
  40.     if( ::is_permutation( std::begin( array1 ), std::end( array1 ), std::begin( array2 ), std::end( array2 ) ) )
  41.     {
  42.         std::cout<< " Elements are permutation of each other\n"; 
  43.     }
  44.     else
  45.     {
  46.         std::cout<< " Elements are not permutation of each other\n";
  47.     }
  48.  
  49.     const std::vector< int > vec1 { { 1, 3, 2, 4 } };
  50.     const std::vector< int > vec2 { { 1, 2, 4, 3 } };
  51.  
  52.     if( ::is_permutation( std::begin( vec1 ), std::end( vec1 ), std::begin( vec2 ), std::end( vec2 ) ) )
  53.     {
  54.         std::cout<< " Elements are permutation of each other\n"; 
  55.     }
  56.     else
  57.     {
  58.         std::cout<< " Elements are not permutation of each other\n";
  59.     }
  60.  
  61.     const std::list< int > list1 { { 1, 3, 2, 4 } };
  62.     const std::list< int > list2 { { 1, 2, 4, 3 } };
  63.  
  64.     if( ::is_permutation( std::begin( list1 ), std::end( list1 ), std::begin( list2 ), std::end( list2 ) ) )
  65.     {
  66.         std::cout<< " Elements are permutation of each other\n"; 
  67.     }
  68.     else
  69.     {
  70.         std::cout<< " Elements are not permutation of each other\n";
  71.     }
  72.     return 0;
  73. }
Success #stdin #stdout 0s 3232KB
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 Elements are not permutation of each other
 Elements are permutation of each other
 Elements are permutation of each other
https://ideone.com/6qj7sk
language:
C++14 (gcc 8.3)
created:
10 years ago
visibility:
public

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